Hi Dears I have got following results:" for open boundary condition" SWEEP=8, MAXSTATES=400, L=200, E0= -0.44220777784 SWEEP=50, MAXSTATES=500, L=200, E0= -0.4422077778446504 SWEEP=8, MAXSTATES=150, L=600, E0= -0.442833001737 SWEEP=8, MAXSTATES= 500, L=600, E0=- 0.44283300822 SWEEP=8, MAXSTATES= 150, L=700, E0= -0.442877
We see that the result still have not got to -0.443147.maybe we increase the size ,getting to this energy but it takes a lot of time . for periodic boundary condition the energy that achieved is lower. I have a question. Are there some techniques for use of this algorithm such that, for example, for 100 or 200 sites we get to the desire energy?
Dear Zhian,
The energy does not depend on the algorithm. A finite system will always have an energy that is different than the energy in the thermodynamic limit, no matter what method you use. What you have to do is a finite size scaling. Plot the energies as a function of 1/L and extrapolate to zero, to get an estimate, and then compare that value to the Bethe anzats result.
Saludos, <ADRIAN>
zhian asadzadeh wrote:
Hi Dears I have got following results:" for open boundary condition" SWEEP=8, MAXSTATES=400, L=200, E0= -0.44220777784 SWEEP=50, MAXSTATES=500, L=200, E0= -0.4422077778446504 SWEEP=8, MAXSTATES=150, L=600, E0= -0.442833001737 SWEEP=8, MAXSTATES= 500, L=600, E0=- 0.44283300822 SWEEP=8, MAXSTATES= 150, L=700, E0= -0.442877
We see that the result still have not got to -0.443147.maybe we increase the size ,getting to this energy but it takes a lot of time . for periodic boundary condition the energy that achieved is lower. I have a question. Are there some techniques for use of this algorithm such that, for example, for 100 or 200 sites we get to the desire energy?
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