Hi,all
This is my interpretation of the relationship between vertex, edge and
operator. Am I right?
Considering 1D Kondo-Heisenberg model, for example:
(1) I shall have two types of vertices - spin and fermion;
(2) Three types of edges - fermion to fermion, fermion to spin and spin to
spin (considering superexchange interaction between spins);
(3) For operators, I shall have - type0 fermion_hop(i,j) related to fermion
to fermion edge, type1 exchange(i,j) related to fermion to spin
(Kondo-exchange interaction) and type2 exchange(i,j) (superexchange);
If I am right, does that mean the number of types of bond operators should
be the same as the number of types of edges defined in the unitcell?
The other question is: in the unitcell of this simple 1D Kondo-Heisenberg
model, I have two-type vertices and three different types of edges, but I
do not define the coordinates as your online example "A complex example" in
section "How to specify graphs corresponding to a lattice with a unit
cell", then is the unitcell which I define 1D or 2D? I think it is 2D, am I
right?
Bo-Nan
--
Stay foolish,Stay hungry.