DMRG for Antiferromagnetic spin one half chain - Comp-phys-alps-users

13 Dec 2008

      Hi Dears
I  have got following results:" for open boundary condition"
SWEEP=8, MAXSTATES=400, L=200, E0= -0.44220777784
SWEEP=50, MAXSTATES=500, L=200, E0= -0.4422077778446504
SWEEP=8, MAXSTATES=150, L=600, E0= -0.442833001737
SWEEP=8, MAXSTATES= 500, L=600, E0=- 0.44283300822
SWEEP=8, MAXSTATES= 150, L=700, E0= -0.442877
We see that the result still have not got to -0.443147.maybe we increase the
size ,getting to this energy but it takes a lot of time . for periodic
boundary condition the energy that achieved is lower.
I have a question. Are there some techniques for use of this algorithm such
that, for example, for 100 or 200 sites we get to the desire energy?
On Sun, Dec 7, 2008 at 6:00 AM,
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Today's Topics:

DMRG For Antiferromagnetic spin one half chain (zhian asadzadeh)
Re: DMRG For Antiferromagnetic spin one half chain
(Matthias Troyer)
Re: DMRG For Antiferromagnetic spin one half chain
(Adrian E. Feiguin)

Message: 1
Date: Sat, 6 Dec 2008 07:58:46 -0500
From: "zhian asadzadeh" zhian.asadzadeh@gmail.com
Subject: [ALPS-users] DMRG For Antiferromagnetic spin one half chain
To: comp-phys-alps-users@phys.ethz.ch
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       89e5d6760812060458j27784855jaf87d27a63e2b4c1@mail.gmail.com
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Hi Dears
Thanks a  lot. I have achieved the ground state energy  as follow:
SWEEP=8, L=30,MAXSTATES=100, E0= -0.437045191.
SWEEP=8, L=50,MAXSTATES=140, E0= -0.43944220.
SWEEP=4, L=100,MAXSTATES=100, E0= -0.44127739.
SWEEP=4, L=100,MAXSTATES=300, E0= -0.44127739.
SWEEP=4, L=300,MAXSTATES=100, E0= -0.44127739.
The E0= -0.44127739 is the best enegy that i achieve and when i change the
sweep&M&L,the energy doesn't change.I can't improve the result ,also i
wrote
the model & lattice, but have not changed any thing.
Thanks.
On Fri, Dec 5, 2008 at 6:00 AM,
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Today's Topics:

DMRG For Antiferromagnetic Spin one half chain (zhian asadzadeh)
Re: DMRG For Antiferromagnetic Spin one half chain
(Matthias Troyer)
Re: DMRG For Antiferromagnetic Spin one half chain
(Adrian E. Feiguin)

Message: 1
Date: Thu, 4 Dec 2008 22:35:51 +0330
From: "zhian asadzadeh" zhian.asadzadeh@gmail.com
Subject: [ALPS-users] DMRG For Antiferromagnetic Spin one half chain
To: comp-phys-alps-users@phys.ethz.ch
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       89e5d6760812041105w5556998du756af1c79c8fb32b@mail.gmail.com
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Hi Dear
Thanks for your consideration.I run the program for different sizes and
have
increased it to 500 sites.For up to 100 site the result converges but it
is
...
not the result that should it be (*0.443147*),the result  that have
achieved
earlier from Bethe method and in the work of Mr.white that tests the DMRG
for showing the powerful of this code.
Thanks
zhian
On Wed, Dec 3, 2008 at 2:30 PM,
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Today's Topics:

DMRG for antiferromagnetic spin one half chain (zhian asadzadeh)
Re: DMRG for antiferromagnetic spin one half chain
(Matthias Troyer)

Message: 1
Date: Tue, 2 Dec 2008 16:43:12 +0330
From: "zhian asadzadeh" zhian.asadzadeh@gmail.com
Subject: [ALPS-users] DMRG for antiferromagnetic spin one half chain
To: comp-phys-alps-users@phys.ethz.ch
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       89e5d6760812020513q686feb0bge51a267945421f2@mail.gmail.com
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Hi ADRIAN
I run DMRG program for  antiferromagnetic S=1/2 chain,but the result
that
...
i
...
achieve for groun state energy  doesn't concur with the result  that
has
...
...
achieved from bethe ansats method (0.443147).
I have changed m&sweep& number of sites(to 1000 site) but my result
just
...
2
...
digit concur with 0.443147.
I don't know what must i do.
I will be very appreciate  if you can guide me.
Thanks
zhian