Well, there are multiple factors that makes it more computationally expensive, but not really thousand times…
The relevant factor are:
- hamiltonian terms are applied on two-sites, i.e. each will cost M^2*d^2. when you change from spinless d=2 to spinfull d=4, you are at least 4 times slower
- because of the fermionic sign, each term in the trotter decomposition requires multiple operations
- the compression to keep the MPS of a controllable dimension is done using an iterative scheme. depending on how strong you are compressing, it might take more iterations
Best,
Michele
Thank you. I have indeed overlooked this important parameter.
It now works smoothly with spinless fermions or bosons. However for spinful fermions the time it takes is more than a thousand times (or more) longer. Even for tiny 2D systems the time it takes is huge. Is it a known limitation and is there a physical reason?
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