I think you need:
<INHOMOGENEOUS><EDGE/></INHOMOGENEOUS>

For the second case, you need to define a graph with different edge types, then you can assign the values in the parameters with:
coeff0=…
coeff1=…
…


Note that there is no automatic lattice graph for an all-to-all graph. This you need to define yourself in a graph file.


Michele


On 28 Jun 2017, at 09:38, John Ian Kenneth E. Felismino <jfelismino@nip.upd.edu.ph> wrote:

Hello again.

I tried using an inhomogenous periodic 1D chain lattice defined as

<LATTICEGRAPH name = "inhomogeneous periodic chain lattice" vt_skip="true">
  <FINITELATTICE>
    <LATTICE ref="chain lattice"/>
    <EXTENT dimension="1" size="L"/>
    <BOUNDARY type="periodic"/>
  </FINITELATTICE>
  <UNITCELL ref="simple1d"/>
  <INHOMOGENEOUS><VERTEX/></INHOMOGENEOUS>
</LATTICEGRAPH>

and it still didn't work.

For the second solution, how do you assign coefficients for every source and target? I need to find the difference for varying (long) ranges.

Thanks.
Ian Felismino


On Wed, Jun 28, 2017 at 12:53 PM, Michele Dolfi <dolfim@phys.ethz.ch> wrote:
Actually both the “abs” and “^” operators seem to be allowed, but the problem might come from the (i-j) term.
Using the coordinates in the coefficients is instead a non-trivial feature. It only works if you define the lattice as inhomogeneous. You should see some examples non the lattices.xml file.

As an alternative solution, you could define the lattice as a graph and set independent coefficients on the bonds and edges. You should find other examples in the mailing list, or on this page https://alps.comp-phys.org/mediawiki/index.php/Tutorials:LatticeHOWTO:SimpleGraphs


Best,
Michele


On 27 Jun 2017, at 08:14, John Ian Kenneth E. Felismino <jfelismino@nip.upd.edu.ph> wrote:

Hi!

The hamiltonian I'm using is attached as a picture file. As you can see, the bond terms are proportional to abs(i - j)^\alpha. i was wondering if this is possible in Alps because I have tried doing it (crudely) with DMRG and found that it did not produce an output xml. I had simply added the term "/abs(i-j)^alpha#" in my hamiltonian.  When I remove this term, the Hamiltonian works, so clearly the problem is with this proportionality term.

Thanks.
Ian Felismino
<Kitaev Hamiltonian.png>

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